Ice cream ladder — a STAR tie in both rounds, settled without the lot (BV2180, fp62p2)¶
Method: STAR (single winner) · 1 seat · Expected winner: Strawberry · full count →
▶ Live on BetterVoting: vote · results ↗ (election fp62p2).
🪜 The happy-path tiebreak. This is the worked example from the STAR tie-breaking ladder, now a live election. It ties in both rounds — a three-way tie for the second finalist, then a two-way tie in the runoff — and settles both with deterministic rungs (five-star, then score). The pre-published lot order is never consulted, so LH and BetterVoting agree and the result is fully reproducible. It's the deliberate contrast to BV555/
xmyf7k, where every rung ties down to the random floor.
Level 201/301. Two voters, six ice-cream flavors. Winner: Strawberry.
The ballots (2 voters)¶
Chocolate, Chocolate Chip, Fudge Brownie, Vanilla, Strawberry, Mango
4, 5, 4, 1, 2, -
1, 0, 0, 4, 5, 4
(- = left blank ≡ 0.) Source: bv2180_fp62p2_ice_cream_ladder.yaml.
How the winner is found — the ladder in action¶
| Step | What happens | Rung that decides |
|---|---|---|
| Scoring round | Strawberry 7 leads; Chocolate, Chocolate Chip, Vanilla tie at 5 for the 2nd slot | — (tie) |
| Scoring tiebreak 1 | pairwise among the three: all 2 → still tied | pairwise (no-op) |
| Scoring tiebreak 2 | five-star count: Chocolate Chip 1, Chocolate 0, Vanilla 0 → advances | five-star ✓ |
| Runoff | Strawberry 1 vs Chocolate Chip 1 head-to-head → tied | — (tie) |
| Runoff tiebreak 1 | total score: Strawberry 7 > Chocolate Chip 5 → wins | score ✓ |
Both ties resolve before the lot. The elegant part (see the ladder doc): each round breaks its tie with the other round's yardstick — a scoring-round tie (equal totals) is broken by the runoff's pairwise, then five-star; a runoff tie (equal preference) is broken by the scoring round's total score.
View 1 — BetterVoting (fp62p2)¶
BetterVoting runs the same protocol; because no random rung is reached, it elects Strawberry too.
📷 Paste the BetterVoting
fp62p2result screenshot here (filename suffix_fp62p2, underimg/).
View 2 — the LH engine (reference)¶
[Divergence from STAR]
STAR = Strawberry
Choose-One (Plurality) = Chocolate Chip (differs from STAR)
Approval = Chocolate (differs from STAR)
--- STAR Voting Method (single winner) ---
[STAR Voting]
Tabulating 2 ballots.
Chocolate,Chocolate Chip,Fudge Brownie,Vanilla,Strawberry,Mango
4, 5, 4, 1, 2, -
1, 0, 0, 4, 5, 4
('-' = left blank / abstained; '0' = scored zero — both count as 0 stars.)
[STAR Voting: Scoring Round]
The two highest-scoring candidates advance to the next round.
Strawberry -- 7 -- First place
Chocolate -- 5 -- Tied for second place
Chocolate Chip -- 5 -- Tied for second place
Vanilla -- 5 -- Tied for second place
Fudge Brownie -- 4
Mango -- 4
Strawberry advances, but there's a three-way tie for second.
[STAR Voting: Scoring Round: First tiebreaker]
The candidate preferred in the most head-to-head matchups advances.
Chocolate -- 2 -- Tied for second place
Chocolate Chip -- 2 -- Tied for second place
Vanilla -- 2 -- Tied for second place
Equal Support -- 0
There's still a three-way tie for second.
[STAR Voting: Scoring Round: Second tiebreaker]
The candidate with the most votes of score 5 advances.
Chocolate Chip -- 1 -- Second place
Chocolate -- 0
Vanilla -- 0
Strawberry and Chocolate Chip advance.
[STAR Voting: Automatic Runoff Round]
The candidate preferred in the most head-to-head matchups wins.
Chocolate Chip -- 1 -- Tied for first place
Strawberry -- 1 -- Tied for first place
Equal Support -- 0
There's a two-way tie for first.
[STAR Voting: Automatic Runoff Round: First tiebreaker]
The highest-scoring candidate wins.
Strawberry -- 7 -- First place
Chocolate Chip -- 5
Strawberry wins.
[STAR Voting: Winner — STAR Voting Method (single winner)]
Strawberry
Full audit copy: _tabulated.
BV vs LH¶
Both engines elect Strawberry — confirmed against BetterVoting's frozen export (_bv_export.json), whose Results record tieBreakType: five_star for the scoring round: BV broke the three-way tie by the five-star count, exactly as LH does. Unlike the 3-way dead heat, they must agree here: every tie is broken by a deterministic rung (five-star, then score), so no random shuffle is reached. That's what makes this case freezable / BV-backable where BV555/xmyf7k is LH-only.
See also¶
- The STAR tie-breaking ladder (full chain) — this is its worked example
- BV555 /
xmyf7k— the 3-way tie that reaches the random floor (the contrast case) - Dead-rung tie-breaks — when five-star has no 5s to weigh