Same matrix, different plurality — electorate P1: Choose-One¶

Generated from same_matrix_p1_plurality.yaml — do not edit by hand. Regenerate: python STARVote_LH_tabulation_engine/tools_adam/scripts/build_yaml_pages.py.

Method: plurality · 1 seat · Expected winner: Ada

Scenario¶

The same electorate P1, voting Choose-One: each voter marks only their first choice, so the ballot keeps the top of the ranking and discards the rest. Tally: Ada 5, Cal 4, Ben 3 — winner Ada. The Ranked Robin file on this same electorate elects Ben, and all three electorates in this folder share one pairwise table while their plurality winners differ. Plurality's winner is not a function of the pairwise matrix.

Ballots¶

Row 1 = candidate names; each later row is one voter's 0–5 scores (a N × prefix = N identical ballots).

Count:Ada,Ben,Cal
4:1,0,0
1:1,0,0
4:0,0,1
3:0,1,0

What the engine says¶

Full report from the _tabulated mirror (regenerated on every run; every analysis forced on):

--- Choose-One / Plurality Voting Method (single winner) ---
 Tabulating 12 ballots.

                    Ada    Ben    Cal  
  5 ×                X      -      -   
  4 ×                -      -      X   
  3 ×                -      X      -   

  Count the marks:  Ada 5 · Cal 4 · Ben 3

Winner — Choose-One / Plurality Voting Method (single winner)
 Ada   (5 of 12 marks)

Run it yourself:

python STARVote_LH_tabulation_engine/starvote_larry_hastings.py method_comparisons/same_matrix_different_plurality/cases/same_matrix_p1_plurality.yaml

Same matrix, different plurality — electorate P1: Choose-One¶

Scenario¶

Ballots¶

What the engine says¶

See also¶