The Black Curtain¶

Generated from Black_Curtain_04_c4_b5_four-candidates.yaml — do not edit by hand. Regenerate: python STARVote_LH_tabulation_engine/tools_adam/scripts/build_yaml_pages.py.

Method: STAR (single winner) · 1 seat · Expected winner: Cal

Scenario¶

Election 4 of 4 from "The Black Curtain". Four candidates now, but behind the curtain (first choices only) it looks identical to the other three: Cal 3, Ann 2. Choose-One, RCV-IRV, and STAR elect Cal. Approval ("approve" = video score 5+) is a 3–3 coin toss between Cal and Dee. Pure Score on the video's 0–9 ballots elects Bob by a hair (avg 5.6 vs Cal's 5.4) — a margin too fine to survive the 0–5 rescale (totals here: Cal 15, Bob 14). Scale granularity is part of the lesson; see README_black_curtain.md. Source video: https://www.youtube.com/watch?v=5_ZMruwOZgw Notes doc: https://docs.google.com/document/d/1ntOS5PQ_kkPnaZpDeqLShGv2pz_k6Zom9LnTEdjjd4o BetterVoting template: https://bettervoting.com/p9gwc3/vote This folder on GitHub: https://github.com/masiarek/YAML/tree/master/method_comparisons/black_curtain Original 0–9 video scores mapped to 0–5: 0→0, 1→1, 4→2, 5→3, 8→4, 9→5.

Ballots¶

Row 1 = candidate names; each later row is one voter's 0–5 scores (a N × prefix = N identical ballots).

Ann,Bob,Cal,Dee
0,2,5,3   # voter 1 — video 0-9: A=0 B=4 C=9 D=5
0,2,5,3   # voter 2 — video 0-9: A=0 B=4 C=9 D=5
0,2,5,3   # voter 3 — video 0-9: A=0 B=4 C=9 D=5
5,4,0,1   # voter 4 — video 0-9: A=9 B=8 C=0 D=1
5,4,0,1   # voter 5 — video 0-9: A=9 B=8 C=0 D=1

What the engine says¶

The count, step by step — the rounds and how the winner is reached:

--- STAR Voting Method (single winner) ---

[STAR Voting]
 Tabulating 5 ballots.
Count × Ann,Bob,Cal,Dee
    3 ×   0,  2,  5,  3
    2 ×   5,  4,  0,  1

[STAR Voting: Scoring Round]
 The two highest-scoring candidates advance to the next round.
   Cal           -- 15 -- First place
   Bob           -- 14 -- Second place
   Dee           -- 11
   Ann           -- 10
 Cal and Bob advance.

[STAR Voting: Automatic Runoff Round]
 The candidate preferred in the most head-to-head matchups wins.
   Cal           -- 3 -- First place
   Bob           -- 2
   Equal Support -- 0
 Cal wins.
   Runoff math:
     5  ballots cast
   − 0  Equal Support (no preference between the two finalists)
     ─
     5  voters with a preference  (majority = 3)
           Cal 3 (60%)  ·  Bob 2 (40%)

[STAR Voting: Winner — STAR Voting Method (single winner)]
 Cal

Full audit — preference matrix, Condorcet, and score distribution¶

--- Runoff (Preference) Matrix ---
Head-to-head / pairwise comparison
Legend: For - Equal Support - Against
        * indicates Top 2 Finalist
               |     Ann    |  * Bob    |  * Cal    |    Dee    |
-----------------------------------------------------------------
         Ann > |    ---     |2 - 0 - 3  |2 - 0 - 3  |2 - 0 - 3  |
       * Bob > | 3 - 0 - 2  |   ---     |2 - 0 - 3  |2 - 0 - 3  |
       * Cal > | 3 - 0 - 2  |3 - 0 - 2  |   ---     |3 - 0 - 2  |
         Dee > | 3 - 0 - 2  |3 - 0 - 2  |2 - 0 - 3  |   ---     |

[Condorcet Winner]
  Condorcet Winner: Cal — matches the STAR winner

[Condorcet Loser]
  Condorcet Loser: Ann — loses every head-to-head matchup

[Score Distribution] (how many ballots gave each star rating)
                Score
Candidate  5  4  3  2  1  0  | Total   Avg
Ann        2  0  0  0  0  3  |    10   2.0
Bob        0  2  0  3  0  0  |    14   2.8
Cal        3  0  0  0  0  2  |    15   3.0
Dee        0  0  3  0  2  0  |    11   2.2

Everything in one file: the _tabulated mirror (regenerated on every run; every analysis forced on).

Run it yourself:

python STARVote_LH_tabulation_engine/starvote_larry_hastings.py method_comparisons/black_curtain/cases/Black_Curtain_04_c4_b5_four-candidates.yaml

The Black Curtain¶

Scenario¶

Ballots¶

What the engine says¶

Full audit — preference matrix, Condorcet, and score distribution¶

See also¶